神剑山庄资源网 Design By www.hcban.com

方法一:回归实现

def PowerSetsRecursive(items):
  """Use recursive call to return all subsets of items, include empty set"""
  
  if len(items) == 0:
    #if the lsit is empty, return the empty list
    return [[]]
  
  subsets = []
  first_elt = items[0] #first element
  rest_list = items[1:]
  
  #Strategy:Get all subsets of rest_list; for each of those subsets, a full subset list
  #will contain both the original subset as well as a version of the sebset that contains the first_elt
  
  for partial_sebset in PowerSetsRecursive(rest_list):
    subsets.append(partial_sebset)
    next_subset = partial_sebset[:] +[first_elt]
    subsets.append(next_subset)
  return subsets

def PowerSetsRecursive2(items):
  # the power set of the empty set has one element, the empty set
  result = [[]]
  for x in items:
    result.extend([subset + [x] for subset in result])
  return result 

方法二:二进制法

def PowerSetsBinary(items): 
  #generate all combination of N items 
  N = len(items) 
  #enumerate the 2**N possible combinations 
  for i in range(2**N): 
    combo = [] 
    for j in range(N): 
      #test jth bit of integer i 
      if(i  j ) % 2 == 1: 
        combo.append(items[j]) 
    yield combo 

以上这篇Python实现求一个集合所有子集的示例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持。

标签:
python,集合所有子集

神剑山庄资源网 Design By www.hcban.com
神剑山庄资源网 免责声明:本站文章均来自网站采集或用户投稿,网站不提供任何软件下载或自行开发的软件! 如有用户或公司发现本站内容信息存在侵权行为,请邮件告知! 858582#qq.com
神剑山庄资源网 Design By www.hcban.com

评论“Python实现求一个集合所有子集的示例”

暂无Python实现求一个集合所有子集的示例的评论...